x^2=-11x+10

Solution for x^2=-11x+10 equation:

x^2=-11x+10

We move all terms to the left:

x^2-(-11x+10)=0

We get rid of parentheses

x^2+11x-10=0

a = 1; b = 11; c = -10;
Δ = b2-4ac
Δ = 112-4·1·(-10)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{161}}{2*1}=\frac{-11-\sqrt{161}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{161}}{2*1}=\frac{-11+\sqrt{161}}{2}
$